THE COLLEGE HILL INDEPENDENT


THIS WEEK IN MIDNIGHT DODGEBALL: PROBLEM SET #1

Let omega be the sum of all players in this experiment. 'A' will stand for team A, whose letters, {a,b,c, etc}, stand for players on team A. And 'B' stands for team B, whose numbers, {1,2,3, etc}, stand for the players on team B. A=B at the start of this experiment, lest a large, hairy Russian, 'r', plays on A. Then A=B-2. Statisticians call this scaling the equation to account for population density differences.

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Omega=A+B=a,b,c, etc + 1,2,3, etc.
When the game begins A intersects with B until A or B reaches 0.
This equation relies on human behavior to balance itself. Some equations work harder than others.
As A or B decreases, the jail for its respective team increases. This is known as negative correlation. Dodgeball can best be elucidated when viewed as a series of relationships.
If a ball makes contact with a player, his/her team, A or B, becomes A-1 or B-1. Players work together to prevent math from piling up. Some players even catch balls, which looks like this statistically, if A catches B's ball, A+1 while B-1. The players who catch these balls usually are worst at tabulating this type of math. They leave it to others.
This is one of an infinite series of outcomes in dodgeball, known to mathematics and chaos theoreticians as a random experiment:
Summator Equation of A, B, where A=B-2=8 (remember a large, hairy Russian, r, plays on A) initially:
A, A-1, A-2, A-3, A-3+1, A-3, A-4, A-5 (the Russian plays alone), A-4 (the Russian catches 4's ball).
B, B-1, B-2, B-3, B-4, B-3, B-4, B-5, B-6, B-7, B-8.
A=1 when B=0. A wins, even though a Russian, r, on A did most of the winning.
The level of statistics required to determine how much a Russian, r, won for A, goes beyond the scope of this text.
--MRM